A high school student incorrectly measures the ΔHrxnC49222 C49graphite 22HCO2graphite 2HH22 2H
° of the following chemical equation to be -2200 kJ/mol. Based on this measurement alone, what is the missing change in enthalpy? Please answer in kJ/mol.
HOH (l) + 6O → 4CO (g) + 5HO (l)
HOH (l) → 4C(s) + 5H (g) + 0.5 O (g) Δ° = 327 kJ/mol
(g) → C(s) + O (g) Δ° = ???
(g) + 0.5 O(g) → HO (l) Δ° = -286 kJ/mol
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