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A pendulum clock was moved from a location where g1 = 9.8098 m/s 2
to another location where g2 = 9.7932 m/s 2 . During the move, the length of the clock’s pendulum did not change; nevertheless, the clock lost accuracy. Assuming the clock was perfectly accurate at its previous location, how many seconds a day does it lose at the new location? Answer in units of s.
Could someone help me with the question? I found what the periods would be for each pendulum with different gravities, and got t1=0.3192 and t2=0.3195. Idk where to go from here
 
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The post A pendulum clock was moved from a location where g1 = 9.8098 m/s 2 to another location where g2 = 9.7932 m/s 2 . During the move, the length of the clock’s pendulum did not change; nevertheless, the clock lost accuracy. appeared first on Superb Professors.

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