# An object moving vertically is at the given heights at the speciﬁed times. Find the position equation 5 = %at2 + V0!” + so for the object. (a) At t = 0 seconds, 5 = 160 feet. At t = 1 second, 5 = 93 feet. At t = 2 seconds, 5 = 0 feet. E (b) At t = 1 second, 5 = 132 feet. At t = 2 seconds, .5 = 84 feet. At t = 3 seconds, 5 = 4 feet. E (c) At t = 1 second, 5 = 184 feet. At t = 2 seconds, 5 = 113 feet. At t = 3 seconds, 5 = 16 feet. :l

An object moving vertically is at the given heights at the speciﬁed times. Find the position equation 5 = %at2 + V0!" + so for the object. (a) At t = 0 seconds, 5 = 160 feet. At t = 1 second, 5 = 93 feet. At t = 2 seconds, 5 = 0 feet. E (b) At t = 1 second, 5 = 132 feet. At t = 2 seconds, .5 = 84 feet. At t = 3 seconds, 5 = 4 feet. E (c) At t = 1 second, 5 = 184 feet. At t = 2 seconds, 5 = 113 feet. At t = 3 seconds, 5 = 16 feet. :l

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The post An object moving vertically is at the given heights at the speciﬁed times. Find the position equation 5 = %at2 + V0!” + so for the object. (a) At t = 0 seconds, 5 = 160 feet. At t = 1 second, 5 = 93 feet. At t = 2 seconds, 5 = 0 feet. E (b) At t = 1 second, 5 = 132 feet. At t = 2 seconds, .5 = 84 feet. At t = 3 seconds, 5 = 4 feet. E (c) At t = 1 second, 5 = 184 feet. At t = 2 seconds, 5 = 113 feet. At t = 3 seconds, 5 = 16 feet. :l appeared first on Superb Professors.