# Given: G = 6.67259 × 10−11 N m2 /kg2 The acceleration of gravity on the surface of a planet of radius R = 4470 km is 3.06 m/s 2 . What is the period T of a satellite in circular orbit h = 6615.6 km above the surface? Answer in units of s.

Given: G = 6.67259 × 10−11 N m2 /kg2 The acceleration of gravity on

the surface of a planet of radius R = 4470 km is 3.06 m/s 2 . What is the period T of a satellite in circular orbit h = 6615.6 km above the surface? Answer in units of s.

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The post Given: G = 6.67259 × 10−11 N m2 /kg2 The acceleration of gravity on the surface of a planet of radius R = 4470 km is 3.06 m/s 2 . What is the period T of a satellite in circular orbit h = 6615.6 km above the surface? Answer in units of s. appeared first on Superb Professors.