Suppose you ran this same reaction (using the balloon setup as seen
in the video) on your own with two different flasks. In Flask A, you reacted 5.10 g Mg with 0.447 mol HCl. In Flask B, you reacted 24.21 g Mg with 0.998 mol HCl. Which ballon will inflate the most? Explain (in detail) why, showing all work.
Mg + 2HCl = MgCl2 + H2
This is the anwser to the above question:
In this reaction the ratio of reactants is 1:2.
In Flask A – 5.10 g/ (24.305 g/mol) = 0.20983 mol Mg
In Flask B – 24.21g/(24.305 g/mol) = .99607 mol Mg
Flask A – .20983 mol Mg/.447 mol HCl < ½
Mg is limiting reactant
Flask B – .99607 mol Mg/.998 mol HCl > ½
HCl is limiting reactant
Balloon A – ratio of Mg to H2 is 1:1
.20983 mols H2 generated
Balloon B – ratio of HCl to H2 is 2:1
.998 mols HCl/2 = .499 mols H2 generated
Balloon B inflates the m
How do you find the mol ratio what is the 24.305 g/mol where would i get that info? i see the math but dont know where the formula numbers came from
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